Question:
Answer:
Question 1.
The decreasing order of first ionization energy is-
Li > Na > K > Rb
As the atomic radius increases then the removal of electrons becomes easy.
Also, the ionization energy decreases from top to bottom in groups, and increases from left to right across a period. Thus, helium has the highest first ionization energy, while francium has the lowest.
Question 2.
The decreasing order of first ionization energy is-
Kr > Br > As > Se > Ge > Ca > Ga > K
The first ionization energy of an element is the energy needed to remove the outermost electron from a neutral atom in the gas phase.
Outermost electrons for the given elements are-
Kr = 4p6
Br = 4p5
As = 4p3
Se = 4p4
Ge = 4p2
Ca = 4s2
Ga = 4p1
K = 4s1
As has higher first ionization energy than Se because As has stable half-filled p3 configuration.