### Question:

Give the chemical symbol for the element with the ground state electron configuration [Ar]4s^23d^3

### Answer:

**Answer No 1:**

**The chemical symbol for the element with the ground state electron configuration [Ar]4s ^{2}3d^{3} is ‘V’.**

__Explanation:__

The total electrons present in Argon [Ar] are 18.

So, there are total (18+2+3)=23 electrons present in the [Ar]4s^{2}3d^{3} electron configuration.

Therefore, 23 is the Atomic number of __ ‘Vanadium’__ whose chemical symbol is

**.**

__‘V’__

__Answer No.2:__

**For 4s : n=4**

**For 4s : l = 0**

**Explanation:**

In the question ‘n’ is called** ‘Principal Quantum Number**‘ , ‘l’ is called **‘Azimuthal Quantum Number’** .

**1. Principal Quantum Number(n):**

It determines the energy of an electron in an orbit where electron is present.

**For 4s ,the value of the principal quantum number (n) is 4.**

**2. Azimuthal Quantum Number(l):**

It determines the number of subshells to which the electrons belong.

**The value of l = (n-1) always where n is the number of principle Quantum Number.**

**For 4s, the value of ‘l’ is 0.**

**Answer no.3**

**The possible values of m _{l }for the 4s subshell is ‘0’.**

**Explanation:**

*Magnetic Quantum Number(m _{l}):*

It gives the number of permitted orientations of orbitals.

**The value of ‘m _{l}‘ varies from ‘-l’ to ‘+l’ through zero.**

**In the question , for 4s, the value of ‘l’ is 0. So the value of Magnetic Quantum Number(m _{l}) is 0.**

**Answer no.4:**

**For 3d : n = 3**

**For 3d : l = 2**

**Explanation:**

In the question ‘n’ is called **‘Principal Quantum Number’ **, ‘l’ is called **‘Azimuthal Quantum Number’ .**

**1. Principal Quantum Number(n):**

It determines the energy of an electron in an orbit where electron is present.

**For 3d ,the value of the principal quantum number (n) is 3.**

**2. Azimuthal Quantum Number(l):**

It determines the number of subshells to which the electrons belong.

**The value of l = (n-1) always where n is the number of principle Quantum Number.**

**For 3d, the value of ‘l’ is 2.**

**Answer no.5:**

**The possible values of m _{l }for the 3d subshell are ‘-2,-1,0,+1,+2‘.**

**Explanation:**

*Magnetic Quantum Number(m _{l}):*

It gives the number of permitted orientations of orbitals.

**The value of ‘m _{l}‘ varies from ‘-l’ to ‘+l’ through zero.**

**In the question , for 3d, the value of ‘l’ is 2. So the value of Magnetic Quantum Number(m _{l}) is ‘-2,-1,0,+1,+2’.**