# Give the chemical symbol for the element with the ground state electron configuration

### Question:

Give the chemical symbol for the element with the ground state electron configuration [Ar]4s^23d^3

The chemical symbol for the element with the ground state electron configuration [Ar]4s23d3 is ‘V’.

Explanation:

The total electrons present in Argon [Ar] are 18.

So, there are total (18+2+3)=23 electrons present in the [Ar]4s23d3 electron configuration.

Therefore, 23 is the Atomic number of ‘Vanadium’ whose chemical symbol is ‘V’.

For 4s : n=4

For 4s : l = 0

Explanation:

In the question ‘n’ is called ‘Principal Quantum Number‘ , ‘l’ is called ‘Azimuthal Quantum Number’ .

1. Principal Quantum Number(n):

It determines the energy of an electron in an orbit where electron is present.

For 4s ,the value of the principal quantum number (n) is 4.

2. Azimuthal Quantum Number(l):

It determines the number of subshells to which the electrons belong.

The value of l = (n-1) always where n is the number of principle Quantum Number.

For 4s, the value of ‘l’ is 0.

The possible values of mfor the 4s subshell is ‘0’.

Explanation:

Magnetic Quantum Number(ml):

It gives the number of permitted orientations of orbitals.

The value of ‘ml‘ varies from ‘-l’ to ‘+l’ through zero.

In the question , for 4s, the value of ‘l’ is 0. So the value of Magnetic Quantum Number(ml) is 0.

For 3d : n = 3

For 3d : l = 2

Explanation:

In the question ‘n’ is called ‘Principal Quantum Number’ , ‘l’ is called ‘Azimuthal Quantum Number’ .

1. Principal Quantum Number(n):

It determines the energy of an electron in an orbit where electron is present.

For 3d ,the value of the principal quantum number (n) is 3.

2. Azimuthal Quantum Number(l):

It determines the number of subshells to which the electrons belong.

The value of l = (n-1) always where n is the number of principle Quantum Number.

For 3d, the value of ‘l’ is 2.